Saturday, 29 October 2011

Modulus

You may or may not be aware of what modulus is. If you have come across the modulus (absolute value) of a number before it is likely to only be of real numbers. The notation for the modulus of x is, |x|.

If the number is just a real number then calculating the modulus is incredibly easy and requires no thought. Essentially it is just 'taking the positive value' of the number, for example: |5| is simply 5, and |-3| = 3. It follows that any rational or irrational real number is just the positive value of it. The definition of |x| for any real value of x therefore follows that |x| = √(x²).

Another, potentially easier way to think of the modulus of a number, is to think of the numbers distance from 0 on a number line. -5 is 5 units away from 0 and 5 is also 5 units away from 0. This thought is useful when it comes to finding the modulus of a complex number.

Complex numbers can also be represented (in a way) on a number line, they are represented in a two-dimensional complex plane. A complex number, 5+3i will be 5 units in the x direction and 3 units in the y direction, therefore the general form of a complex number is x+iy.

As I said previously, to find the modulus of a complex number it helps if we think of our previous definition of |x| being the distance from 0 on a number line (or a complex plane, in this case). If we think of it in this manner then simple co-ordinate geometry states that the distance from 0 to x+iy is √[(x-0)²+(y-0)²], or simply the general definition of |x+iy| = √(x²+y²).

|x| = √(x²) when x is a real number, and this able to be proved from our new definition of |x+iy|. |x+iy| = √(x²+y²), and when x+iy is a real number, y has to equal 0, plugging this into the equation we get |x+i0| = √(x²+0²), therefore |x| = √(x²), proved.

If any of this was explained poorly or just went straight over your head please comment and I will do everything I can to make it understandable. Also if you would like more information on imaginary numbers please visit an older post of mine here.

Thursday, 6 October 2011

Squaring Numbers Under 100

First, I must state that although you do not necessarily require any prior knowledge other than to be competent at maths, it does not hurt if you know the square numbers up to 10 and are reasonably good at quadratic equations.

I recently discovered this technique of timesing numbers together recently and I was pretty proud of myself and have been using to bamboozle my friends and family. However I did not create this technique, I do not know who did, but if you do please leave a comment.

I am starting by squaring a number, as the skills learnt from that will help you when you times two different numbers together, which I will cover in a later blog post.

To begin with when squaring a number we need to choose one number as a base, we will call it 'a', for example if we had 43 our base would be 40. If we had 47 however I would personally choose 50, as dealing with 3 is easier than dealing with 7. This second number we will call, 'n', to get 'n' you take the base from the original number, 'o'.

n = o-a

You may see where we are going here, we will take the equation (a+n) and square it, that is all we have to do. The product of this will be a²+2an+n². So for example if we wanted to find the answer to 76²:

a = 80, n = 76-80 = -4
80²+2(80*-4)+(-4)²
6400-640+16 = 5776

After a little bit of practice you can do this very efficiently and very quickly in your head.

I am alive!

Clearly I haven't been posting nearly as much as I should have. Things have unfortunately got in the way, what with my GCSE exams, starting college etc. But now I am back, well, for now. A fair few of my points may be on contents of AS Maths and Further Maths, but there is likely to be many mathematical tricks and the hidden gems of maths in there too. Anyway, I just thought I would update you will on my current situation and my hopeful resurgence to the world of blogging.